2(4x^2+5x)+4(10-2x^2)=140

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Solution for 2(4x^2+5x)+4(10-2x^2)=140 equation:


Simplifying
2(4x2 + 5x) + 4(10 + -2x2) = 140

Reorder the terms:
2(5x + 4x2) + 4(10 + -2x2) = 140
(5x * 2 + 4x2 * 2) + 4(10 + -2x2) = 140
(10x + 8x2) + 4(10 + -2x2) = 140
10x + 8x2 + (10 * 4 + -2x2 * 4) = 140
10x + 8x2 + (40 + -8x2) = 140

Reorder the terms:
40 + 10x + 8x2 + -8x2 = 140

Combine like terms: 8x2 + -8x2 = 0
40 + 10x + 0 = 140
40 + 10x = 140

Solving
40 + 10x = 140

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + 10x = 140 + -40

Combine like terms: 40 + -40 = 0
0 + 10x = 140 + -40
10x = 140 + -40

Combine like terms: 140 + -40 = 100
10x = 100

Divide each side by '10'.
x = 10

Simplifying
x = 10

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